Subject: Re: [xsl] problem reqarding link From: "Joga Singh Rawat jrawat@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 18 Jan 2024 11:37:03 -0000 |
Thanks an lot Michael!!! From: Michael Kay mike@xxxxxxxxxxxx [mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx] Sent: 18 January 2024 14:31 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] problem reqarding link The simplest approach would be to change <xsl:for-each select="key('ids', .)"> to <xsl:for-each select="key('ids', translate(., '#', ''))"> to strip out the '#' character. This would be applied to @id attributes as well as @href attributes, but if the @id attributes never contain a "#", that's fine. Michael Kay Saxonica On 18 Jan 2024, at 08:02, Joga Singh Rawat jrawat@xxxxxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: Hi Team, I am not able to get required OUTPUT of @sn <link> because of hash (#) problem. Please help in this regard. Input <html> <p>Textb& <a href=b#bibxb class=bbibcitb>1</a> xxx <a href=b#bibyb class=bbibcitb>2</a></p> <p class=bBib_entryb id=bbibxb>xxxxxxxxxxxx</p> <p class=bBib_entryb id=bbibyb>xxxxxxxxxxxx</p> </html> output <html> <p>Textb& <link rid=bbibxb class=bbibcitb sn=b1b>1</link> xxx <link rid=bbibyb class=bbibcitb sn=b2b>2</a></p> <bib id=bbibxb sn=b1b>xxxxxxxxxxxx</bib> <bib id=bbibyb sn=b2b>xxxxxxxxxxxx</bib> </html> Xsl <xsl:key name="ids" match="p[@class = 'Bib_entry'] use="@id"/> <xsl:template match="p[@class='Bib_entry']/@id | @href"> <xsl:for-each select="key('ids', .)"> <xsl:if test="name(.)= 'p'"> <xsl:text/> <xsl:number format="1" count="p[@class = 'Bib_entry']" level="any" from="html"/> </xsl:if> </xsl:for-each> </xsl:template> <xsl:template match="a"> <xsl:variable name="rid" select="substring-after(@href, '#')"/> <xsl:choose> <xsl:when test="@class = 'bibcit'"> <link class=bbibcitb> <xsl:attribute name="rid"> <xsl:value-of select="$rid"/> </xsl:attribute> <xsl:attribute name="sn"> <xsl:apply-templates select="@href"/> </xsl:attribute> <xsl:apply-templates/> </link> </xsl:when> </xsl:choose> </xsl:template> <xsl:template match="p[@class='Bib_entry']"> <bib> <xsl:call-template name="id"/> <xsl:attribute name="sn"> <xsl:apply-templates select="@id"/> </xsl:attribute> <xsl:apply-templates/> </bib> </xsl:template> Thanks a lot in advance b&JSR <http://www.mulberrytech.com/xsl/xsl-list> XSL-List info and archive EasyUnsubscribe <http://lists.mulberrytech.com/unsub/xsl-list/293509> (by email) Click here <https://www.mailcontrol.com/sr/Iuw_9ItPYQvGX2PQPOmvUrvxg9nfQreSuSmdBA6I-sPP9 pVVEl9RWlntwcE72iBW1wLVgp83_gmoZTw26POg4w==> to report this email as spam. XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list> EasyUnsubscribe <http://lists.mulberrytech.com/unsub/xsl-list/876847> (by email <> )
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