Re: [xsl] problem reqarding link

Hi,

An alternative is to look at it the other way by wiring it into your key:

<xsl:key name="ids" match="p[@class = 'Bib_entry'] use="'#' || @id"/>

Which approach is better depends on the case. Naming the key helps make sense
of it:

<xsl:key name="bib-entry-references" match="p[@class = 'Bib_entry'] use="'#'
|| @id"/>

Cheers, Wendell

From: Joga Singh Rawat jrawat@xxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, January 18, 2024 6:38 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] problem reqarding link

Thanks an lot Michael!!!

From: Michael Kay mike@xxxxxxxxxxxx<mailto:mike@xxxxxxxxxxxx>
[mailto:xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx]
Sent: 18 January 2024 14:31
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx<mailto:xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: Re: [xsl] problem reqarding link

The simplest approach would be to change

<xsl:for-each select="key('ids', .)">

to

<xsl:for-each select="key('ids', translate(., '#', ''))">

to strip out the '#' character. This would be applied to @id attributes as
well as @href attributes, but if the @id attributes never contain a "#",
that's fine.

Michael Kay
Saxonica

On 18 Jan 2024, at 08:02, Joga Singh Rawat
jrawat@xxxxxxxxxxxxxx<mailto:jrawat@xxxxxxxxxxxxxx>
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx<mailto:xsl-list-service@xxxxxxxxxxxx
rytech.com>> wrote:

Hi Team,
I am not able to get required OUTPUT of @sn <link> because of hash (#)
problem.  Please help in this regard.

Input
<html>
<p>Text... <a href="#bibx" class="bibcit">1</a>  xxx <a href="#biby"
class="bibcit">2</a></p>
<p class="Bib_entry" id='bibx">xxxxxxxxxxxx</p>
<p class="Bib_entry" id='biby">xxxxxxxxxxxx</p>
</html>

output
<html>
<p>Text... <link rid="bibx" class="bibcit" sn="1">1</link>  xxx <link
rid="biby" class="bibcit" sn="2">2</a></p>
<bib id='bibx" sn="1">xxxxxxxxxxxx</bib>
<bib id='biby" sn="2">xxxxxxxxxxxx</bib>
</html>

Xsl
<xsl:key name="ids" match="p[@class = 'Bib_entry'] use="@id"/>

<xsl:template match="p[@class='Bib_entry']/@id | @href">
<xsl:for-each select="key('ids', .)">
  <xsl:if test="name(.)= 'p'">
   <xsl:text/>
   <xsl:number format="1" count="p[@class = 'Bib_entry']" level="any"
from="html"/>
  </xsl:if>
</xsl:for-each>
</xsl:template>

<xsl:template match="a">
<xsl:variable name="rid" select="substring-after(@href, '#')"/>
<xsl:choose>
  <xsl:when test="@class = 'bibcit'">
   <link class="bibcit">
      <xsl:attribute name="rid">
       <xsl:value-of select="$rid"/>
      </xsl:attribute>
    <xsl:attribute name="sn">
     <xsl:apply-templates select="@href"/>
    </xsl:attribute>
    <xsl:apply-templates/>
   </link>
  </xsl:when>
</xsl:choose>
</xsl:template>

<xsl:template match="p[@class='Bib_entry']">
<bib>
  <xsl:call-template name="id"/>
  <xsl:attribute name="sn">
   <xsl:apply-templates select="@id"/>
  </xsl:attribute>
  <xsl:apply-templates/>
</bib>
</xsl:template>

Thanks a lot in advance
...JSR
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