Subject: Re: [xsl] Getting all the text of an element, except for one type From: "Bauman, Syd s.bauman@xxxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 9 Feb 2024 14:05:39 -0000 |
There are many ways to skin this cat. Here is one: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="3.0"> <xsl:output indent="yes"/> <xsl:mode on-no-match="shallow-copy"/> <xsl:template match="/pub"> <xsl:copy> <xsl:apply-templates select="section/title"/> </xsl:copy> </xsl:template> <xsl:template match="title"> <entry><xsl:apply-templates/></entry> </xsl:template> <xsl:template match="title/data"/> </xsl:stylesheet> ________________________________ Hi All. Here is my input: <?xml version="1.0" encoding="UTF-8"?> <pub> <section> <title>This is my clever title with <ph>a phrase</ph> and some data.<data>12345</data></title> <p>A plain paragraph.</p> </section> <section> <title>Another title without any children.</title> <p>Another plain paragraph.</p> </section> </pub> I want to get all of the text from the <title> elements are its children, except for <data> elements: <?xml version="1.0" encoding="UTF-8"?> <pub> <entry>This is my clever title with a phrase and some data. </entry> <entry>Another title without any children.</entry> </pub> Here is my stylesheet but I am missing something in my understanding. Thanks in advance for your help. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:math="http://www.w3.org/2005/xpath-functions/math" exclude-result-prefixes="xs math" version="3.0" expand-text="yes"> <xsl:output indent="yes"/> <xsl:template match="/pub"> <xsl:copy> <xsl:apply-templates select="section"/> </xsl:copy> </xsl:template> <xsl:template match="section"> <entry><xsl:value-of select="title/descendant-or-self::* except data"/></entry> </xsl:template> </xsl:stylesheet>
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