Re: [xsl] Getting all the text of an element, except for one type

["Michael Kay michaelkay90@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

> Here is my stylesheet but I am missing something in my understanding. Thanks
in advance for your help.
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>     xmlns:xs="http://www.w3.org/2001/XMLSchema";
>     xmlns:math="http://www.w3.org/2005/xpath-functions/math";
>     exclude-result-prefixes="xs math"
>     version="3.0" expand-text="yes">
>
>     <xsl:output indent="yes"/>
>
>     <xsl:template match="/pub">
>         <xsl:copy>
>             <xsl:apply-templates select="section"/>
>         </xsl:copy>
>     </xsl:template>
>
>     <xsl:template match="section">
>         <entry><xsl:value-of select="title/descendant-or-self::* except
data"/></entry>
>     </xsl:template>
>
> </xsl:stylesheet>
>

What you are missing is that `<xsl:value-of
select="title/descendant-or-self::* except data"/>` concatenates the string
values of all the selected elements, including the `title` element and the
`ph` element, and the string value of an element is the concatenation of all
its descendant text nodes.

I would recommend using the recursive descent approach using template rules.
However, an alternative would be

<xsl:value-of select="title/descendant::text() except title//data/text()"
separator=""/>

Michael Kay
Saxonica