Essentially OK. But if you do your timing exactly right, you don't need to
do the STA WSYNC.
That is, you have a full 76 cycles available to do your stuff, so if you use
exactly 76 cycles, you're smack bang set for starting the next scan line
without requiring the WSYNC write. That's my understanding.
A
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----- Original Message -----
From: "John K. Harvey" <jkharvey@xxxxxxxxxxxxxxxxx>
To: <stella@xxxxxxxxxxx>
Sent: Thursday, September 14, 2000 3:33 PM
Subject: [stella] Elementary question
> Hi again.
>
> I am pretty sure this is right, but I need to verify that it is, so I
don't
> look like a fool when trying to explain this. Or maybe it's just late,
and
> I'm second-guessing myself.
>
> Just to verify:
> A scanline has 76 cycles. STA WSYNC takes 3 cycles.
> So, in simple code:
>
> STA WSYNC ;takes you to the end of the previous scanline
>
> ; This scanline:
> ; Use 73 cycles
> STA WSYNC ; will give you a total of 76 cycles, an entirely FULL scanline
>
> ; And we begin our next scanline, right at the beginning...
>
> So, is that correct?
>
> -John K. Harvey
>
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