Hi Greg!
> Erik Mooney wrote:
> > 3/25/2002 9:18:01 AM, cybergoth@xxxxxxxx wrote:
> > Careful here - Classic sorting algorithms are usually defined as
> > speed being the number of swaps required. In tightly timed
> > 6502 assembly language, the comparisons and looping take a
> > quite significant amount of time already. In the example
> > of 7, 1, 2, 3, 4, 5, 6, you require n^2 comparisons (actually
> > (n-1)^2) to get the 7 to the end of the list.
> Actually, the classic bubble sort implementation requires 6 comparisons
> to get the 7 into the proper place, then one more pass to notice that
> the data is now in sorted order. You compare 7 to 1 and swap it, then 7
> to 2, then 7 to 3, etc.
Well, that depends on the sort order. Since Thomas rversed it
somewhere at the beginning of the Thread, this was my example
for a worst case. Now you sort again the other way round, so the
worst case (which is what we were talking about) would now be
inserting a zero at the end :-)
Greetings,
Manuel
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