Subject: Re: [xsl] passing parameters to an import file From: "cutlass" <cutlass@xxxxxxxxxxx> Date: Mon, 10 Sep 2001 12:19:18 +0100 |
try using the with-param <xsl:call-template name=""> <xsl:with-param name="" select=""/> </xsl:call-template> though i suspect this may not be supported across all parsers with document() calls, and not quite sure if it is supported at all, will be interesting to know though. cheers, jim fuller ----- Original Message ----- From: "Tanzila Mohammad" <tmohammad@xxxxxxxxxxxxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Monday, September 10, 2001 12:18 PM Subject: [xsl] passing parameters to an import file > I have a xsl stylesheet (main.xsl) which imports another xsl stylesheet > (common.xsl). > > Within main.xsl there is the following code: > > <xsl:call-template name="noResults"/> <!--noResults is contained within the > common.xsl--> > > However, common.xsl requires a parameter which is utilized by the noResults > template, is there a way to pass the parameter to the template from main.xsl > via the call? > > Something like this: > > <xsl:call-template name="noResults(<xsl:value-of select="$param"/>)"/> > > Thanks > > Tanzila > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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