Subject: Re: [xsl] catching the last node still satisfying a condition From: "Dimitar Peikov" <mitko@xxxxxxx> Date: Thu, 13 Sep 2001 17:51:27 +0300 |
> > Exactly, but I've cant find the right words. Sorry for > > misunderstanding. The result is quite the same, isn't it? > > I've no idea whether the result is the same, since I've no idea what you > mean by "recordsets" and "arrays" in an XPath context. > > If you're trying to say that XPath collections are sets rather than > sequences, and that you therefore can't index them positionally, then that's > obviously wrong. > > Mike Kay > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > Yes. This is true that all is collection. But collections like arrays can be iterated to fetch the data you need. Testing one condition can return one element collection. But if you have repeated sub-nodes the same test condition there must be organized some iterator to distinguish the needed one. Am I right? Or where is my misunderstanding? -- Dimitar Peikov Programmer Analyst Globalization Group "We Build e-Business" RILA Solutions 27 Building, Acad.G.Bonchev Str. 1113 Sofia, Bulgaria phone: (+359 2) 9797320 phone: (+359 2) 9797300 fax: (+359 2) 9733355 http://www.rila.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] catching the last node st, Michael Kay | Thread | RE: [xsl] catching the last node st, Michael Kay |
RE: [xsl] looping without changing , Michael Kay | Date | Re: [xsl] catching the last node st, David Carlisle |
Month |