[xsl] generate xsl 1.0 from 2.0 question

["Bryan Rasmussen" <bry@xxxxxxxxxx>]

I want to generate xslt 1.0 from 2.0(am obviously using saxon 7), here's a
structure I had in my old xslt(when I was generating multiple xslt from xslt
1.0) for translating some strings that I output at different parts:



<xsl:param name="translate"
select="document('../generating_documents/languages.xml')"/>
<xsl:param name="translator" select="$translate/translations/string"/>

<xsl:template name="translator">
<temp:when test="/page[@language='{name()}']"><xsl:value-of
select="."/></temp:when>
</xsl:template>



<xsl:template name="click_here"><temp:choose><xsl:for-each
select="$translator[@name='Click_here']/child::node()[name()!='']">
<xsl:call-template name="translator"/></xsl:for-each></temp:choose>
</xsl:template>

(didn't use xml:lang in the translator template cause I ran into some
problems that took longer than an hour to fix, and there were too many other
things to fix at the time.)
anyway the thing I was wondering about is in the template name="click_here"
you'll notice I do the $translator[@name='Click_here'] is there anyway to
select the name of the template one is in(in xslt 2.0), in such a way that I
could make a parameter holding the template/@name value and pass it to a
named template through a call?





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