Subject: RE: [xsl] generate xsl 1.0 from 2.0 question From: "Bryan Rasmussen" <bry@xxxxxxxxxx> Date: Wed, 23 Jan 2002 12:11:23 +0100 |
thanks jeni, I came to sort of the same conclusion(our posts crossed), post starts with line about coffee kicking in. ><xsl:template name="createChoose"> ><xsl:param name="translatorName" /> > <temp:choose> > <xsl:for-each select="$translator[@name = $translatorName] > /(* | processing-instruction())"> > <xsl:call-template name="translator" /> > </xsl:for-each> > </temp:choose> ></xsl:template> >[Note that I've swapped the child::node()[name() != ''] for something> >that explicitly selects the nodes that have names (i.e. elements and >processing instructions) using XPath 2.0 general steps. I suspect that >you're just after the elements, in which case you could just use >$translator[@name = $translatorName]/*.] yep I was just after the elements. :) thanks again. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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