Subject: Re: [xsl] Can I take only parts from node value? From: "Robert Koberg" <rob@xxxxxxxxxx> Date: Tue, 19 Feb 2002 08:07:32 -0800 |
If they are always in that format you could use the substring function. I would leave it this format because it will be easier to sort. best, -Rob ----- Original Message ----- From: "jp" <jp@xxxxxxxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Tuesday, February 19, 2002 7:58 AM Subject: [xsl] Can I take only parts from node value? > Hi, > > If I have XML-tag like this: > > <today date="200202190800" /> > > and I want output: > > Time is 08:00 > Date is 19.02 > Year is 2002 > > How can I do this with XSL/T? Or should I change XML output? > > Regs, > -JP > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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