Subject: [xsl] XPath iteration? From: Derek Davies <ddavies@xxxxxxxxxxxxxxx> Date: Thu, 11 Jul 2002 18:12:45 -0400 |
Hi, I'm sorry if this question is inappropriate here, but I haven't found a more appropriate place to ask, nor have I found a FAQ that addresses my question. I'm trying to come up with an XPath expression that will "iterate". What I have in mind is something to the effect of: /Root/SomeNode[position()!=position(/Root/SomeNode)] which would compare each SomeNode against all other SomeNode's except itself (there are multiple SomeNode children of /Root). I don't want to explicitly enumerate the SomeNode's. I have a feeling this isn't possible in XPath (I know it's trivial with XSL). Would someone care to shed some light on this for me? Thanks, Derek XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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