Subject: [xsl] Using an index with a sorted list of elements From: "Hugh Dixon" <hugh.dixon@xxxxxxxxxxxxxx> Date: Wed, 19 Mar 2003 16:33:04 +1100 |
I have a number of elements, similar to <element @value/> I want to find the element that has the biggest value of "value" less than a value $upperBound. Eg <elements> <element value = "10"/> <element value = "80"/> <element value = "100"/> <element value = "5"/> </elements> If $upperBound is 85, I want <element value = "80"/> If $upperBound is 7, I want <element value = "5"/> I am trying to do something like: <xsl:for-each select="element[$upperBound>./@value][1]"> <xsl:sort data-type="number" select="./@value" order="descending"/> <xsl:value-of select="."/> </xsl:for-each> However the [1] is being applied before the sort (ie I sort a single element!) I cannot figure out where to stick my [1]!!!! Is this the best way to do this? What is the correct syntax for what I'm trying to accomplish? Thanks!!! XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] what does xsl:sort do if , Michael Kay | Thread | Re: [xsl] Using an index with a sor, bix_xslt |
[xsl] what does xsl:sort do if "sel, Robert P. J. Day | Date | [xsl] Re: what does xsl:sort do if , Dimitre Novatchev |
Month |