Subject: [xsl] Re: what does xsl:sort do if "select" doesn't evaluate to anything? From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Wed, 19 Mar 2003 07:07:44 +0100 |
"Robert P. J. Day" <rpjday@xxxxxxxxxxxxxx> wrote in message news:Pine.LNX.4.44.0303182306400.26300-100000@xxxxxxx > > what is the defined behavior for <xsl:sort> if the "select=" > expression is not satisfied by anything? > > eg., i want to process a bunch of <car> elements, sorted by their > engine <displacement> values, but some of the <car> elements have no > such element? If the "data-type" attribute of xsl:sort is "text" then: For these elements the sort key "displacement" will evaluate to the empty string. Depending on how a particular XSLT processor implements string comparison in xsl:sort all "car" elements with no "displacement" children will be sorted together (with "car" elements that have a "displacement" with empty string value) as a group either preceding or following all "car" elements, which have "dis[lacement" children with non-empty string value. If the "data-type" attribute of xsl:sort is "number" then the value of the sort key "displacement" will be NaN -- and they will be sorted again as a group -- first or last depending on the implementation. ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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