Subject: RE: [xsl] xsl:if giving me "Invalid type" error From: "Passin, Tom" <tpassin@xxxxxxxxxxxx> Date: Tue, 15 Apr 2003 15:39:08 -0400 |
[James J. Ramsey] > I was trying to store the name of whatever the first > top-level <div*> was. Maybe > > <xsl:variable name="firstDiv"> > <xsl copy-of > select="(div[1]|div0[1]|div1[1]|divGen[1])[1]"/> > </xsl:variable> > > would work better for what I need to do (which is to > keep track of that first top-level <div*>)? > That won't do it either. You will get a result tree fragment, not a node-set. Just write <xsl:variable name='firstDiv' select='(div[1]|div0[1]|div1[1]|divGen[1])[1]'/> This __does__ select a node-set - of course, you better have the right xpath expression in there!. Remember, Simple Is Good. Cheers, Tom P XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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