RE: [xsl] xsl:if giving me "Invalid type" error

Subject: RE: [xsl] xsl:if giving me "Invalid type" error
From: "Passin, Tom" <tpassin@xxxxxxxxxxxx>
Date: Tue, 15 Apr 2003 15:39:08 -0400
[James J. Ramsey]

> I was trying to store the name of whatever the first
> top-level <div*> was. Maybe
> 
> <xsl:variable name="firstDiv">
>   <xsl copy-of
> select="(div[1]|div0[1]|div1[1]|divGen[1])[1]"/>
> </xsl:variable>
> 
> would work better for what I need to do (which is to
> keep track of that first top-level <div*>)?
> 

That won't do it either.  You will get a result tree fragment, not a
node-set.  Just write 

<xsl:variable name='firstDiv'
   select='(div[1]|div0[1]|div1[1]|divGen[1])[1]'/>

This __does__ select a node-set - of course, you better have the right
xpath expression in there!.

Remember, Simple Is Good.

Cheers,

Tom P

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