Subject: Re: [xsl] xsl:if giving me "Invalid type" error From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Tue, 15 Apr 2003 16:11:58 -0400 |
> How have you declared $firstDiv?
It is a string. :(
I was trying to store the name of whatever the first top-level <div*> was. Maybe
<xsl:variable name="firstDiv"> <xsl copy-of select="(div[1]|div0[1]|div1[1]|divGen[1])[1]"/> </xsl:variable>
would work better for what I need to do (which is to keep track of that first top-level <div*>)?
Cheers, Wendell
__________________________________________________ Do you Yahoo!? The New Yahoo! Search - Faster. Easier. Bingo http://search.yahoo.com
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] xsl:if giving me "Invalid, Wendell Piez | Thread | RE: [xsl] xsl:if giving me "Invalid, Passin, Tom |
RE: [xsl] template match for subele, Kathy Burke | Date | Re: [xsl] xsl:if giving me "Invalid, Wendell Piez |
Month |