Subject: Re: [xsl] Count() nodes ?? From: Koteswararao Mogili <raomvk@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 16 Sep 2003 12:02:36 -0400 |
try this too count(//Root/FixedNodes/Node[@name=1]/*)On Tuesday, September 16, 2003, at 11:41 AM, xsl-list@xxxxxxxxxxxxxxxxxxxxxx wrote:
did u try count(//Root/FixedNodes/Node[@name=1])
--Rao On Tuesday, September 16, 2003, at 11:24 AM, xsl-list@xxxxxxxxxxxxxxxxxxxxxx wrote:
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-listHi,
I am having the following xml document.
<Root> <FixedNodes> <Node name="1"> <Subnode myAtt="itsValue"/> <Subnode myAtt="itsValue"/> <Subnode myAtt="itsValue"/> </Node> <Node name="2"> <Subnode myAtt="itsValue"> <Subnode myAtt="itsValue"> <Subnode myAtt="itsValue"> <Subnode myAtt="itsValue"> </Node> </FixedNodes> <VaryingNodes> <Node name="3"> <Subnode myAtt="itsValue"> <Subnode myAtt="itsValue"> </Node> </VaryingNodes> </Root>
How do i count number of Subnode within FixedNodes.
I tried using
"count(//Root/FixedNodes/Node/Subnode)
But i got count as zero. Is this because there is attribute associated
with
each of the Node element ?
Can someone please tell me how do i count it ? Thanks in the anticipation that I will get some reply.
Regards, Dipesh
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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