Subject: Re: [xsl] Modifying the xPath order... From: i92agcad@xxxxxx Date: Mon, 01 Mar 2004 11:33:36 +0100 (MET) |
I'm sorry... my english is very poor My question is... I use a <xsl:sort> inside a <xsl:for-each> but this order (ascending) isn't available to use axis like (preceding:: , preceding-sibling::, etc...) When i use this axis the order of the elements still be the order in XML document and i want to work with the order created with <xsl:sort> ok?¿? Mensaje citado por: Andrew Curry <andrew.curry@xxxxxxxxxxxx>: > What are you wanting to do exacly, i think im missing your question > ----- Original Message ----- > From: <i92agcad@xxxxxx> > To: "Lista XSL" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> > Sent: Monday, March 01, 2004 9:32 AM > Subject: [xsl] Modifying the xPath order... > > > > I have this structure in XML... > > <elements> > <element>5</element> > <element>3</element> > <element>6</element> > <element>1</element> > </elements> > > With XSL, i have... > > <xsl:for-each select="element"> > <xsl:sort select="." order="ascending" data-type="number"/> > ... > </xsl:for-each> > > In this way, the elements have this order... > > position() = 1 --> element = 1 > position() = 2 --> element = 3 > position() = 3 --> element = 5 > position() = 4 --> element = 6 > > But ... > > preceding of element = 1 is element = 6 > preceding of element = 3 is element = 5 > preceding of element = 5 is element = null > preceding of element = 6 is element = 3 > > Then, how i know that preceding of element=3 in the order is the > element = > 1? > ¿? > > How i calculate the acumulated total?¿? (for the element = 5 the total > acumulated is 1 + 3 + 5 ...) > > Thanks!!! > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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