Subject: [xsl] Detecting item types within a sequence (XSLT2.0/XPath2.0) From: Colin Granger <colgranger@xxxxxxxxxxx> Date: Thu, 28 Oct 2004 16:13:08 +0100 (BST) |
Hi, Sequences can contain mixed item types, but is there any way of detecting the item type of each item within a sequence in XSLT2.0/XPath2.0/XQuery? For example, in XSLT2.0... <?xml version="1.0"?> <xsl:stylesheet version="2.0" exclude-result-prefixes="xs" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:template match="/"> <xsl:variable name="foo"> <aaa>aaa</aaa> <aaa>bbb</aaa> </xsl:variable> <xsl:variable name="bar" select="(xs:date('2004-10-30'), 1.1, 'A', $foo/*)"/> <output> <xsl:for-each select="$bar"> <xsl:variable name="this" select="."/> <xsl:text> Item </xsl:text> <xsl:value-of select="position()"/> <xsl:text> of sequence is... </xsl:text> <!-- detect item type here? is this a node/attribute/document/namespace or a simple type?? --> </xsl:for-each> <xsl:text> </xsl:text> </output> </xsl:template> </xsl:stylesheet> the output I'd like to obtain would be someting like... <output> Item 1 of sequence is a... xs:date Item 2 of sequence is... xs:decimal Item 3 of sequence is... xs:string Item 4 of sequence is... a node of some kind Item 5 of sequence is... a node of some kind </output> or at least... <output> Item 1 of sequence is... not a node of any kind Item 2 of sequence is... not a node of any kind Item 3 of sequence is... not a node of any kind Item 4 of sequence is... a node of some kind Item 5 of sequence is... a node of some kind </output> Many Thanks Colin Send instant messages to your online friends http://uk.messenger.yahoo.com
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