Re: [xsl] xsl templates match does not work

[josh higgins <doopsterus@xxxxxxxxx>]

will it matter if I have a row element is a different
item in my xml?  I suppose it would so I should use my
xpath.

Thanks Buddy!

--- David Carlisle <davidc@xxxxxxxxx> wrote:
> 
> > I am calling it as follows.
> 
> I thought you might be:-)
> 
>  <xsl:template match="/">
> 
> so here the current node is the root node.
> and that is still the case here
> 			
> <xsl:call-template name="summaryTable"/>
> 
> so you need to use any XPath's relative to that so
> header/row/total_due
> not just total_due
> 
> Or perhaps simpler change
> 
> <xsl:template name="summaryTable">
> 
> 
> to 
> 
> <xsl:template match="row">
> 
> and change
> 
> 				<xsl:call-template name="summaryTable"/>
> 
> 
> to 
> 
> <xsl:apply-templates select="header/row"/>
> 
> so that the current node when your template is
> executed is the row node.
> 
> David
> 
>
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