Subject: RE: [xsl] Need help OR'ing in XPATH. From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 22 Mar 2006 09:13:44 -0000 |
Juts translate your English into XPath directly... > For my contrived example below, I would like to select select=" > all book nodes book > whose [ > owner is "aaa" owner='aaa' > *or* or > which have a chapter whose owner is > "aaa", chapter/owner='aaa']" Putting that together: select="book[owner is "aaa" or chapter/owner='aaa'] ALternatively you could write select="book[owner is "aaa"] | book[chapter/owner='aaa'] The "|" operator here forms the union of two sets. In both cases the results will be in document order, as required. Michael Kay http://www.saxonica.com/ and > I would like the books to be retrieved in the same general > order as the > xml document, i.e., the query for the example below would > process books > with id's 1, 3, 4 (in that order), not 1, 4, 3. > > I can do the XPATH for *either* of the two cases, but don't > know how to > combine the two for an OR search in my xsl:apply-templates > select statement. > > <xsl:a-t select="book[owner='aaa'] or book/chapter[owner='aaa']"/> > > is kind of what I want, but Xalan is complaining that my select > attribute is just returning a boolean, so my syntax is > apparently wrong. > > Any help would be much appreciated. > > Thanks, > Glen > > > <book id="1"> > <owner>aaa</owner> > <chapter> > <owner>bbb</owner> > </chapter> > <chapter> > <owner>ccc</owner> > </chapter> > </book> > <book id="2"> > <owner>bbb</owner> > <chapter> > <owner>bbb</owner> > </chapter> > <chapter> > <owner>ccc</owner> > </chapter> > </book> > <book id="3"> > <owner>ccc</owner> > <chapter> > <owner>aaa</owner> > </chapter> > <chapter> > <owner>ccc</owner> > </chapter> > </book> > <book id="4"> > <owner>aaa</owner> > <chapter> > <owner>bbb</owner> > </chapter> > <chapter> > <owner>ccc</owner> > </chapter> > </book>
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