Subject: Re: [xsl] Need help OR'ing in XPATH. From: Glen Mazza <grm7793@xxxxxxxxxxx> Date: Wed, 22 Mar 2006 07:24:51 -0500 |
-------- Mensaje original -------- Asunto: Re: [xsl] Need help OR'ing in XPATH. Fecha: Wed, 22 Mar 2006 14:25:38 +0530 De: Mukul Gandhi <gandhi.mukul@xxxxxxxxx> Responder a:: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Referencias: <4420F165.2070309@xxxxxxxxxxx>
Please try this
<xsl:apply-templates select="book[(owner = 'aaa') or (chapter/owner = 'aaa')]" />
Regards, Mukul
On 3/22/06, Glen Mazza <grm7793@xxxxxxxxxxx> wrote:
Hello,
For my contrived example below, I would like to select all book nodes whose owner is "aaa" *or* which have a chapter whose owner is "aaa", and I would like the books to be retrieved in the same general order as the xml document, i.e., the query for the example below would process books with id's 1, 3, 4 (in that order), not 1, 4, 3.
I can do the XPATH for *either* of the two cases, but don't know how to
combine the two for an OR search in my xsl:apply-templates select statement.
<xsl:a-t select="book[owner='aaa'] or book/chapter[owner='aaa']"/>
is kind of what I want, but Xalan is complaining that my select attribute is just returning a boolean, so my syntax is apparently wrong.
Any help would be much appreciated.
Thanks, Glen
<book id="1"> <owner>aaa</owner> <chapter> <owner>bbb</owner> </chapter> <chapter> <owner>ccc</owner> </chapter> </book> <book id="2"> <owner>bbb</owner> <chapter> <owner>bbb</owner> </chapter> <chapter> <owner>ccc</owner> </chapter> </book> <book id="3"> <owner>ccc</owner> <chapter> <owner>aaa</owner> </chapter> <chapter> <owner>ccc</owner> </chapter> </book> <book id="4"> <owner>aaa</owner> <chapter> <owner>bbb</owner> </chapter> <chapter> <owner>ccc</owner> </chapter> </book>
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