Subject: RE: [xsl] XSL 1.1 -> Asking for an attribut namespace From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 29 Mar 2006 16:10:25 +0100 |
name() should return the lexical QName of the attribute, that is "fo:text-align". However, you don't want to be testing namespace prefixes, because users are allowed to choose any prefix they like. The construct you want is <xsl:copy-of select="..../@fo:*"/> No need for the for-each and the xsl:if. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: news@xxxxxxxxxxx [mailto:news@xxxxxxxxxxx] > Sent: 29 March 2006 15:39 > To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx' > Subject: [xsl] XSL 1.1 -> Asking for an attribut namespace > > Hello List, > > I've a XML: > <?xml version="1.0" encoding="ISO-8859-1" standalone="yes" ?> > <Spalten xmlns:fo="http://www.w3.org/1999/XSL/Format"> > <Datenursprung>//SVERLAUF</Datenursprung> > <Spalte anzahl="1" breite-in-prozent="3" text-align="right"> > <Titel fix="true"></Titel> > <Data fix="true" fo:text-align="right">position()</Data> > </Spalte> > </Spalten> > > The problem I have comes when I try to copy all attributes of > the <Data/> > node into my result dataset. I want to copy each attribut as > long as it has > a namespace of "fo:". > > <xsl:for-each select="$ListData/Spalten/Spalte[$i]/@*"> > <xsl:if test="starts-with(name(), 'fo:')"> > <xsl:copy-of select="."/> > </xsl:if> > </xsl:for-each> > > name() always gives me back the correct name, but without the > namespace of > the attribut. I want to filter ther attributes this way since > I dont want to > have attributes like "anzahl" in my FO result dataset. > > Doeas anybody hase a idea how I can solve my probem? > Thanks & with best regards, Jan
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