Subject: RE: [xsl] Filtering out duplicates in current-group() From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 29 Mar 2006 19:09:17 +0100 |
Just do another level of grouping: <xsl:for-each-group select="current-group()" group-by="Title"> .. output details of this title .. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Smith, Donald [mailto:DSmith@xxxxxxxxxxxxxxxxxxx] > Sent: 29 March 2006 17:32 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Filtering out duplicates in current-group() > > Given this source: > > <Playlist> > <Song order="5" id="c95"> > <Title>Maneater</Title> > <Artist>Hall and Oates</Artist> > <Album>H20</Album> > <Year>1982</Year> > </Song> > <Song order="13" id="c49"> > <Title>Strangers In The Night</Title> > <Artist>Frank Sinatra</Artist> > <Album>Reprise Collection Boxed Set</Album> > <Year>1966</Year> > </Song> > <Song order="8" id="c22"> > <Title>Strangers In The Night</Title> > <Artist>Frank Sinatra</Artist> > <Album>Your Hit Parade - '60s Instrumentals</Album> > <Year>1960</Year> > </Song> > </Playlist> > > And given the following templates from my stylesheet: > > <xsl:template match="Playlist"> > <h1>Songs By Decade</h1> > <xsl:for-each-group select="Song" group-by="substring(Year, 1, 3)"> > <p>Decade: <xsl:value-of select="current-grouping-key()"/>0's</p> > <p style="margin-left: 1pc;"> > <xsl:apply-templates select="current-group()/Title" /> > </p> > </xsl:for-each-group> > </xsl:template> > > <xsl:template match="Title"> > <xsl:apply-templates select="." /><br/> > </xsl:template> > > How do I filter the current group so that the same song doesn't occur > more than once for a decade (that is, so I don't get "Strangers In the > Night" more than once for the 60's)? > > Thanks, > > Don
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