Subject: [xsl] Filtering out duplicates in current-group() From: "Smith, Donald" <DSmith@xxxxxxxxxxxxxxxxxxx> Date: Wed, 29 Mar 2006 10:31:50 -0600 |
Given this source: <Playlist> <Song order="5" id="c95"> <Title>Maneater</Title> <Artist>Hall and Oates</Artist> <Album>H20</Album> <Year>1982</Year> </Song> <Song order="13" id="c49"> <Title>Strangers In The Night</Title> <Artist>Frank Sinatra</Artist> <Album>Reprise Collection Boxed Set</Album> <Year>1966</Year> </Song> <Song order="8" id="c22"> <Title>Strangers In The Night</Title> <Artist>Frank Sinatra</Artist> <Album>Your Hit Parade - '60s Instrumentals</Album> <Year>1960</Year> </Song> </Playlist> And given the following templates from my stylesheet: <xsl:template match="Playlist"> <h1>Songs By Decade</h1> <xsl:for-each-group select="Song" group-by="substring(Year, 1, 3)"> <p>Decade: <xsl:value-of select="current-grouping-key()"/>0's</p> <p style="margin-left: 1pc;"> <xsl:apply-templates select="current-group()/Title" /> </p> </xsl:for-each-group> </xsl:template> <xsl:template match="Title"> <xsl:apply-templates select="." /><br/> </xsl:template> How do I filter the current group so that the same song doesn't occur more than once for a decade (that is, so I don't get "Strangers In the Night" more than once for the 60's)? Thanks, Don
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