Re: [xsl] Return system's date and time

Subject: Re: [xsl] Return system's date and time
From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>
Date: Fri, 18 May 2007 18:44:45 +0530
you could use the function, current-date.

but also, you can truncate time portion in the string 2007-05-18+05:30
easily, using XSLT string handling functions.

On 5/18/07, J. S. Rawat <jrawat@xxxxxxxxxxxxxx> wrote:
Thanks Abel!!!
Need a tips once again. How can we get the system time without timezone.
The result of current-time() is 2007-05-18+05:30 but I want only 2007-05-18.

Thanks
JSR

At 12:04 PM 5/14/2007 +0200, you wrote:
>Abel Braaksma wrote:
>>
>><xsl:stylesheet
>>    xmlns:fn="http://www.w3.org/2005/02/xpath-functions";
>>    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="2.0">
>
>
>Correction (thanks Florent), that should become:
>
><xsl:stylesheet
>   xmlns:fn="http://www.w3.org/2005/xpath-functions";
>   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="2.0">
>
>but is not necessary anyway (again see Florent's comments), so you can do
>without it...
>
>-- Abel
>


--
Regards,
Mukul Gandhi

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