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Subject: Re: SOLUTION FOR : How can I add a new children in a node?? From: "T. Kurt Bond" <tkb@xxxxxxxxxxxxxxxxxxx> Date: Sun, 3 Oct 1999 12:22:52 -0400 (EDT) |
Brandon Ibach writes:
> Quoting Aleksandar Bakic <bakicale@xxxxxxxxxxxxxxxxx>:
> > > You could also write (process-children), or just (pc) if you define it:
> > >
> > > (define (pc) (process-children))
> > >
> > > which is what I do.
> >
> > Sorry if I am a bit off the topic, but can't you define pc like in
> > pure Scheme:
> >
> > (define pc process-children)
> >
> > ?
> >
> Yes. This would bind "pc" to the same procedure object that
> "process-children" is bound to. The other form would, theoretically,
> bind "pc" to a new, zero-argument, procedure object which simply calls
> the procedure to which "process-children" is bound at the time of the
> definition. I would think that a smart Scheme implementation would
> render these two the same, but I'm not positive.
Actually,
(define (pc) (process-children))
will bind pc to a new, zero-argument procedure as you suggested, but
when called it will actually call the procedure that
"process-children" is bound to when "pc" is called. (This is probably
less of a difference in DSSSL than in Scheme, since DSSSL lacks the
imperative features of Scheme.)
To get "pc" to call the procedure that "process-children" was bound to
when "pc" was defined you'd need to do something like this:
(define pc
(let ((old-pc process-children))
(lambda ()
(old-pc))))
--
T. Kurt Bond, tkb@xxxxxxxxxxxxxxxxxxx
DSSSList info and archive: http://www.mulberrytech.com/dsssl/dssslist
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