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Subject: Matching in IDREFS attributes From: Jean Daniel Fekete 8208 <Jean-Daniel.Fekete@xxxxxx> Date: Thu, 15 Jul 1999 19:39:18 +0200 |
Hi,
I am new to this list and, although I searched in the archives and
didn't found any similar request, I may have misread or misunderstood
the specs.
I have XML elements with an ANA attribute of type IDREFS. I want to
iterate over these refs in XSL and create an hypertext link to each
referenced id. I am using TEILite so I have something like:
<NAME ANA="CRIMINEL MASCULIN" KEY="jb">Jehan Basset</NAME> ...
<INTERP ID="CRIMINEL" VALUE="Le Criminel"/>
<INTERP ID="MASCULIN" VALUE="Sexe masculin"/>
and I want:
Jehan Basset (<A HREF="#CRIMINEL">1</A>, <A HREF="#MASCULIN">2</A>)
I don't care too much about what is inside the <A>..</A> though.
2nd problem, probably harder: I would also like to have a two-way
linking where the <INTERP ...> points back to all its references.
Here is how I did it with IE5 "context()" extension to XSL:
<xsl:template match="INTERP">
<xsl:if test="ancestor(TEXT)/BODY//*[@ANA=context()/@ID]">
<DIV><A>
<xsl:attribute name="NAME"><xsl:value-of select="@ID"/></xsl:attribute>
<xsl:value-of select="@VALUE"/>:
</A><SPAN style="color: blue;">
<xsl:for-each select="ancestor(TEXT)/BODY//*[@ANA=context()/@ID]">
<A>
<xsl:attribute name="HREF">#<xsl:value-of select="@ANA"/>-<xsl:eval>ChildNumber(this)</xsl:eval></xsl:attribute>
<xsl:value-of select="."/>
</A>
</xsl:for-each>
</SPAN>
</DIV>
</xsl:if>
</xsl:template>
However, it doesn't work when @ANA is a list since there is no "member
of" operator as far as I know in XSLT.
Is there any way to do it with XSLT?
Jean-Daniel Fekete
Ecole des Mines de Nantes, 4 rue Alfred Kastler, La Chantrerie,
BP 20722, 44307 Nantes Cedex 03, France
Voice: +33-2-51-85-82-08 | Fax: +33-2-51-85-82-49
Jean-Daniel.Fekete@xxxxxx | http://www.emn.fr/fekete/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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