RE: How to use xslt to transform xml to xml with added nodes

[Michael Teigman <michael.teigman@xxxxxxxxxxx>]

Thanks for the response.

I do want to create a static node but I want it to depend on the value of the
other element attribute, e.g.:

<c>
<d e="texte"><f g="textg"/></d>
<d e="texth"><f g="texti"/></d>
</c>

if textg = A or E or I or U then texti = "vowel"
if textg = B or C or D or F or G or H or J then texti = "low consonant"
if textg = K or L or M then texti = "low middle consonant"
....

This is not my actual data text but it gives the idea.
The number of categories for textg could be quite long. Is there some easy way
of doing the match?



                                                                  
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To:   xsl-list@xxxxxxxxxxxxxxxx
cc:    (bcc: Michael Teigman/HPG/US/Reuters)
Subject:  RE: How to use xslt to transform xml to xml with added nodes







> From: Michael Teigman [mailto:michael.teigman@xxxxxxxxxxx]
> Sent: Tuesday, September 14, 1999 6:20 PM
> Subject: How to use xslt to transform xml to xml with added nodes

> ...
> I want to transform it to a new xml keeping all the original intact
> but adding to <c> such that the new xml would be:
> ...

It is not clear to me, how you want to create this additional notes.
If you just intend to include some static content, the following
will do (with XT). It is just a slight variation of what James Clark
gives as the 'identity transformation' in the XSLT spec, see 7.5.
Copying.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/XSL/Transform/1.0";>

 <xsl:template match="@*|*">
  <xsl:copy>
   <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="c">
  <xsl:copy>
   <xsl:apply-templates select="@*|node()"/>
   <d e="texth"><f g="texti"/></d>
  </xsl:copy>
 </xsl:template>

</xsl:stylesheet>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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