Subject: RE: position() of the parent From: "Pawson, David" <DPawson@xxxxxxxxxxx> Date: Thu, 20 Jan 2000 11:45:25 -0000 |
DSSSL permits an absolute node numbering relative to the document root. Is that achievable in XPATH? DaveP >> Worked great! But just for my curiosity, is there any way to find the >> position() of the parent? > >the question is not well formed. Nodes do not, of themselves, have a >position, they only have a position in a node list. > >So for example if you select the parent with .. or parent:: the >position() will be 1, as it will be the first node in a list >of one, but >I assume this isn't what you meant. > >If you mean what is 1 more than the number of preceding >siblings of the >parent, you can do > >select="1+count(../preceding-sibling::*)" > >David > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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