Subject: RE: parameter setting From: "vanaja gogineni" <vanaja_g@xxxxxxxxxxx> Date: Wed, 19 Apr 2000 13:04:02 -0700 |
Thanku I tried like that but still I am unable to get it, I removed select also it is not working . is there any other way pl suggest me. Thanks ®ards vanaja -- On Wed, 19 Apr 2000 09:10:22 Selva, Francis wrote: >Well I guess the reason is you have the string 'output' as ur default value >which overwrites your actual parameter.If you remove the select attribute,it >will work. > >Francis > > >> my xsl looks like this >> ---------------------------------------------- >> it is a top level parameter >> >> <xsl:param name="param1" select="'output'"/> >> >> and I am using this variable in-between >> like this >> >> <xsl:value-of select="$param1"/> >> >> >> result is >> >> "output" >> >> but I want "vanaja" to be displayed >> >> what is the wrong with this >> >> >> Thanks & regards >> >> Vanaja >> > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > __________________________________________________________________ Get your own free England E-mail address at http://www.england.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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