Subject: RE: parameter setting From: prasadm@xxxxxxx Date: Wed, 19 Apr 2000 16:18:57 -0500 |
Use concat function should solve this problem <xsl:value-of select="concat($param1, '')"/> - Prasad > -----Original Message----- > From: vanaja gogineni [SMTP:vanaja_g@xxxxxxxxxxx] > Sent: Wednesday, April 19, 2000 3:04 PM > To: xsl-list@xxxxxxxxxxxxxxxx > Subject: RE: parameter setting > > Thanku > > I tried like that but still > > I am unable to get it, I removed > > select also it is not working . > > is there any other way pl suggest me. > > Thanks ®ards > > vanaja > -- > > On Wed, 19 Apr 2000 09:10:22 Selva, Francis wrote: > >Well I guess the reason is you have the string 'output' as ur default > value > >which overwrites your actual parameter.If you remove the select > attribute,it > >will work. > > > >Francis > > > > > >> my xsl looks like this > >> ---------------------------------------------- > >> it is a top level parameter > >> > >> <xsl:param name="param1" select="'output'"/> > >> > >> and I am using this variable in-between > >> like this > >> > >> <xsl:value-of select="$param1"/> > >> > >> > >> result is > >> > >> "output" > >> > >> but I want "vanaja" to be displayed > >> > >> what is the wrong with this > >> > >> > >> Thanks & regards > >> > >> Vanaja > >> > > > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > > > __________________________________________________________________ > Get your own free England E-mail address at http://www.england.com > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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