Subject: Re: Returning from a call-template or breaking a for-each From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 4 Jul 2000 18:53:29 +0100 (BST) |
> I have written a template looping through a (xt-)node-set and looking for > a node with a given id: But why loop through all the other nodes if you don't want to process them? <xsl:for-each select="xt:node-set($allbookmarks)/BookmarkElement"> <xsl:if test="$bid=Heading/@BookmarkID"> <xsl:value-of select="File" /> # <xsl:value-of select="normalize-space ($bid)" /> </xsl:if> </xsl:for-each> is equivalent to <xsl:value-of select="xt:node-set($allbookmarks)/BookmarkElement[$bid=Heading/@BookmarkID]/File" /> # <xsl:value-of select="normalize-space ($bid)" /> > Now I want to return from this template when I have found the node. Is > there a way to achive this? where do you want to return to? In answer to the question in the subject line, you can't break a for-each loop, but you don't need to, you just select the nodes that you want to loop over in advance. Since the input tree never changes you should be able to work out which modes you want to loop over before starting the loop. David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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