xsl to xsl (xsl creating xsl ouput)

["Carlson, Thor" <CarlsonT@xxxxxxx>]

Using the examples in Mike Kay's book and the XSL-List archive, I used one
XSL stylesheet to create a second stylesheet via the <xsl:namespace-alias>
feature.  I also need to augment the new stylesheet based on an XML source
file (XML + XSL = newXSL).

Given the following XML file:

<INCLUDES>
  <INCLUDE>include1.xsl</INCLUDE>
  <INCLUDE>include2.xsl</INCLUDE>
</INCLUDES>

I want my output stylesheet to include the following in addition to the
hardcoded output:

<xsl:include href="include1.xsl"/>
<xsl:include href="include2.xsl"/>

The following stylesheet outputs XSL except I can't figure out how to
process the input XML file as well (the for-each doesn't run, it is merely
output as more XSL).



<?xml version='1.0' encoding="UTF-8"?>
<x:stylesheet xmlns:x="http://www.w3.org/1999/XSL/Transform";
              xmlns:xsl="anything" version="1.0">
<x:output method="xml" indent="yes"/>
<x:namespace-alias stylesheet-prefix="xsl" result-prefix="x"/>

<!-- everything between the x:template tags 
     is outputted to the new stylesheet 
  -->
  
   <x:template match="/">
      <xsl:stylesheet version="1.0">
      <xsl:template match="/">
         <xsl:value-of select="foobar"/>
      </xsl:template>

      <!-- Create the include lines??? -->
      <x:for-each select="//INCLUDE">
         <xsl:include>
            <xsl:attribute name="href">
               <x:value-of select="."/>
            </xsl:attribute> 
         </xsl:include>
      </x:for-each>

      </xsl:stylesheet>
   </x:template>
</x:stylesheet>


TIA,

----------------------------------
Thor Carlson
Dun & Bradstreet
carlsont@xxxxxxx
973.605.6095 voice
973.605.6957 fax


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