Re: xsl to xsl (xsl creating xsl ouput)

[Oliver Becker <obecker@xxxxxxxxxxxxxxxxxxxxxxx>]

> <?xml version='1.0' encoding="UTF-8"?>
> <x:stylesheet xmlns:x="http://www.w3.org/1999/XSL/Transform";
>               xmlns:xsl="anything" version="1.0">
> <x:output method="xml" indent="yes"/>
> <x:namespace-alias stylesheet-prefix="xsl" result-prefix="x"/>
> 
> <!-- everything between the x:template tags 
>      is outputted to the new stylesheet 
>   -->
>   
>    <x:template match="/">
>       <xsl:stylesheet version="1.0">
>       <xsl:template match="/">
>          <xsl:value-of select="foobar"/>
>       </xsl:template>
> 
>       <!-- Create the include lines??? -->
>       <x:for-each select="//INCLUDE">
>          <xsl:include>

>             <xsl:attribute name="href">
>                <x:value-of select="."/>
>             </xsl:attribute> 
                ^^^
This should be <x:attribute>

>          </xsl:include>
>       </x:for-each>
> 
>       </xsl:stylesheet>
>    </x:template>
> </x:stylesheet>

After applying the "patch" Saxon outputs

<?xml version="1.0" encoding="utf-8"?>
<x:stylesheet xmlns:x="http://www.w3.org/1999/XSL/Transform"; version="1.0">
   <x:template match="/">
      <x:value-of select="foobar"/>
   </x:template>
   <x:include href="include1.xsl"/>
   <x:include href="include2.xsl"/>
</x:stylesheet>

Is this the output you expected?

Cheers,
Oliver


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