Subject: Arbitrarily breaking up a table From: Linus-Lin <LLin@xxxxxxxxxxxxxxx> Date: Fri, 8 Sep 2000 17:32:26 -0400 |
I have the following structure <TABLE> <HEADERROW> <HEADER>a</HEADER> <HEADER>b</HEADER> <HEADER>c</HEADER> </HEADERROW> <DATAROWS> <DATAROW> <DATA>1</DATA> <DATA>1</DATA> <DATA>1</DATA> </DATAROW> <DATAROW> <DATA>2</DATA> <DATA>2</DATA> <DATA>2</DATA> </DATAROW> <DATAROW> <DATA>3</DATA> <DATA>3</DATA> <DATA>3</DATA> </DATAROW> <DATAROW> <DATA>4</DATA> <DATA>4</DATA> <DATA>4</DATA> </DATAROW> <DATAROW> <DATA>5</DATA> <DATA>5</DATA> <DATA>5</DATA> </DATAROW> <DATAROW> <DATA>6</DATA> <DATA>6</DATA> <DATA>6</DATA> </DATAROW> <DATAROW> <DATA>7</DATA> <DATA>7</DATA> <DATA>7</DATA> </DATAROW> <DATAROW> <DATA>8</DATA> <DATA>8</DATA> <DATA>8</DATA> </DATAROW> <DATAROW> <DATA>9</DATA> <DATA>9</DATA> <DATA>9</DATA> </DATAROW> </DATAROWS> </TABLE> Normally a bunch of applied templates could easily create one table with 9 rows. What I need is to generate three tables from the same XML each with its own table header. First table would (arbitrarily) have 5 consective rows (rows 1-5). Second table would have 2 consecutive rows (6-7). Third table would have 2 consective rows (8-9). Can some help with scheme???? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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