Re: Two file problem.

[Eric van der Vlist <vdv@xxxxxxxxxxxx>]

Hi Dave,

Without using an extension, I don't see how you can do it without
scanning both documents.

I would do a first loop on file 1 like you've shown and a second one on
file 2 with a test to handle only the elements which are not in file 1.

Alternatively, but using an extension to convert a rtf into nodeset
(which should not be needed any longer in 1.1), you could create a
nodset with the merge of the 2 files and sort it in your for-each loop.

Hope this helps.

Eric

"Pawson, David" wrote:
> 
> problem.
> 
> Two xml files
> 
> file 1
> <fa>
>   <a name="a1">3</a>
>   <a name="a2">5</a>
>   <a name="a3">2</a>
>   <a name="new">1</a>
> </fa>
> 
> file 2
> <fb>
>   <a name="a1">1</a>
> 
>   <a name="a3">1</a>
>   <a name="a4">2</a>
> </fb>
> 
> required output
> <res>
>    <a name="a1">4</a>
>   <a name="a2">5</a>
>   <a name="a3">3</a>
>   <a name="a4">2</a>
>   <a name="new">1</a>
> </res>
> I.e. I want to sum the corresponding elements to the output file.
> 
> Issues with my present solution.
>   Using a <for-each> on the input document I can add, to the output
>   using
> processor:node-set(document(file-other.xml))/fx/a[@name=current()/@name]
>   the value of the corresponding element from the other file.
> 
>   If  I use file 1 as the main document source, I can catch those
>   which match in file 2, but not those unique to file 2 (<a name="new">
> in the example.)
>   If I use file 2 as the main document source, I can get those
>   which match in file 1, but will miss those which are unique to file 1.
> 
>  Can anyone suggest a method of ensuring that I capture in the output
>  all the <a> elements from either file, without using more extensions
>  if possible. I think its the cup function, but no one has come up
>  with this as an extension even ... or have they?
> 
> TIA DaveP
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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