Re: Using xsl:if to determine if a node is empty.

[Oliver Becker <obecker@xxxxxxxxxxxxxxxxxxxxxxx>]

Roger,

> I am trying to determine if a node is empty so that
> I can print a line or not.  I have tried several different variations of
> template matching and xsl:if statements and have not been able to get
> anywhere.  
> 
> Here is the latest thing that I have tried which seems to match evertime
> through so the text is coming out even on empty tags.
> 
> <xsl:template match="VENDOR_ITEM_NUM">	
> 	<xsl:variable name="empty_tag"></xsl:variable>
> 	<tr>
> 		<td></td>
> 		<td>
> 			<font size="2">
> 			<xsl:if test="$empty_tag != .">

empty_tag is an empty node-set, while . is one node: self::node()
resp. VENDOR_ITEM_NUM.
So the test is always true.

> 			<xsl:value-of select="concat('Vendor Item number:
> ',.)"/>
> 			</xsl:if>
> 			</font>
> 		</td>
> 	</tr>
> </xsl:template>

Have a look at the FAQ to get some clues:
http://www.dpawson.freeserve.co.uk/xsl/N3328.html

Cheers,
Oliver


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