RE: newbie variable question

[Don Bruey <dbruey@xxxxxxxxxxxxxxxxxxxxx>]

You're creating the variable within an <xsl:if> block.  The error message is
correct, it's out of scope at the time you test it. </xsl:if> ends this
variable's lifetime.

Don



> -----Original Message-----
> From: Les Howard [mailto:les@xxxxxxxxxxxxxxx]
> Sent: Tuesday, September 26, 2000 12:02 PM
> To: XSL-List@xxxxxxxxxxxxxxxx
> Subject: newbie variable question
> 
> 
> I'm an XSLT newbie.  I've been trying to get this one thing 
> to work for
> a while now and I just can't get it to work.  I'd apreciate any help
> that anyone can provide:
> 
> What I am trying to do is:
> if there are any grp/type element whose contents are "DMA" I want to
> print out the value of the associated name in that grp.  if 
> there is no
> grp/type element whose contents is "DMA" I want to print out 
> the values
> of the description element.
> 
> my XML that looks like this:
> 
>      <area>
>        <grp>
>          <type>MSA</type>
>          <name>foo</type>
>        </grp>
>        <grp>
>          <type>DMA</type>
>          <name>bar</type>
>        </grp>
>      </area>
>      <description>baz</description>
> 
> and the XSLT I'm working with looks like this
> 
>   <xsl:for-each select="area/grp">
>     <xsl:if test="string(type)='DMA'">
>       <xsl:value-of select="name"/>
>      <xsl:variable name="ValueExists" select="'True'"/>
>     </xsl:if>
>   </xsl:for-each>
> <xsl:if  test="$ValueExists!="'True'">
>  <xsl:value-of select="description" />
> </xsl:if>
> 
> 
> but I keep getting an error:
> 
> A reference to variable or parameter 'ValueExists' cannot be resolved.
> The variable or parameter may not be defined, or it may not 
> be in scope.
> 
> I'm using the MS XSLT translator.  Thanks for any help you 
> can provide,
> 
> Les
> 
> 
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