Subject: RE: How To Access a param from style sheet From: "Weakliem, Gordon" <Gordon.Weakliem@xxxxxxxxxxxxxxx> Date: Wed, 18 Oct 2000 17:47:36 -0600 |
Did you declare the parameter in the stylesheet? <xsl:param name="sortBy" /> > -----Original Message----- > From: Bharat.Chintapally@xxxxxxxxxxxxxxxxx > [mailto:Bharat.Chintapally@xxxxxxxxxxxxxxxxx] > Sent: Wednesday, October 18, 2000 4:23 PM > To: XSL-List@xxxxxxxxxxxxxxxx > Subject: How To Access a param from style sheet > > > Hello: > I am new to XSLT and also to this list. I have a quick > question about > accessing parameters from XSL style sheets. I am using Xalan > XSLT processor > in my servlet to transform XML into HTML using XSL. I am > able to set the > stylesheet param using > > xslProcessor.setStylesheetParam("sortBy", "receiverId"); > > Now I am trying to access this param in the xsl stylesheet to do my > sorting.. I tried something like the following but I am not > having much (/any) luck.. > > <xsl:sort select="*[name() = $sortBy]"/> > > Any help is really appreciated.. > > Thanks > -- bharat > > --------------------------------------------------------------- > Bharat Chintapally > CommerceQuest Inc. > bharat.chintapally@xxxxxxxxxxxxxxxxx > New Phone # 813-639-6478 > --------------------------------------------------------------- > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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