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Subject: [xsl] To pass parameters to function From: "nmartella" <nmartella@xxxxxxxxxxxxx> Date: Thu, 15 Feb 2001 13:02:40 +0100 (added by postmaster@mail.tiscalinet.it) |
Hi.
I'm tring to pass two params to this function
function alignLeft(sValue,nSpaces)
alignLeft=left(sValue+space(nSpaces),nSpaces)
end function
in this way
<xsl:variable name="sVal" select='XXXXX'/>
<xsl:value-of select="xsl:alignLeft($sVal,10)"/>
but MSXML3 give me this error
VBScript Run-Time error
Wrong number of arguments or invalid property setting
If I try following, works
<xsl:value-of select="xsl:alignLeft('XXXXX',10)"/>
I think to wrong use of xsl:variable.
Who help me?
Bye, Nicola
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