Subject: Re: [xsl] To pass parameters to function From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Thu, 15 Feb 2001 12:57:20 +0000 |
Hi Nicola, > <xsl:variable name="sVal" select='XXXXX'/> > <xsl:value-of select="xsl:alignLeft($sVal,10)"/> Here, you're setting the value of the variable $sVal to the node set holding all the XXXXX children of the current node. I think you wanted to pass the string 'XXXXX', in which case you need a couple of extra quotes in there: <xsl:variable name="sVal" select="'XXXXX'" /> A couple of things, though: you shouldn't really be using the XSLT namespace for your own functions - make up one of your own - and you can probably achieve what you want to achieve with foo:alignLeft() in plain XSLT, e.g.: <xsl:variable name="sVal" select="'XXXXX'" /> <xsl:value-of select="substring( concat($sVal, substring(' ', string-length($sVal) + 1)), 1, 10)" /> Or, if you prefer, define a template that does the same thing: <xsl:variable name="large-node-set" select="document('')//node()" /> <xsl:template name="alignLeft"> <xsl:param name="string" /> <xsl:param name="pad" /> <xsl:variable name="padding"> <!-- using the Piez Method for repeating a number of times --> <xsl:for-each select="$large-node-set[position() <= $pad]"> <xsl:text> </xsl:text> </xsl:for-each> </xsl:variable> <xsl:value-of select="substring( concat($string, substring($padding, string-length($string) + 1)), 1, $pad)" /> </xsl:template> and then call it with: <xsl:call-template name="alignLeft"> <xsl:with-param name="string" select="$sVal" /> <xsl:with-param name="pad" select="10" /> </xsl:call-template> Of course this is all based on my guess about what alignLeft does. I hope that helps anyway, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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