RE: [xsl] xsl to xsl doing it right

Subject: RE: [xsl] xsl to xsl doing it right
From: "Alex Reuter" <areuter@xxxxxxxxxxxxxxxx>
Date: Wed, 4 Apr 2001 13:44:09 -0400
Hello List,

Thanks for all your help.  There's something weird going on though in my
attempt to implement your suggestions.
Here is my namespace aliasing code...
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl=""; xmlns:alex=
"alex-namespace" >
<xsl:namespace-alias stylesheet-prefix="xsl" result-prefix="alex"/>
<xsl:output method="xsl"/>
<xsl:template match="/">
<alex:stylesheet version="1.0">

The xml is processed correctly and everything seems to work properly
except....In the output alex is not replaced with xsl.

Any more suggestions?
Thanks again!

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Simon Wickes
Sent: Tuesday, April 03, 2001 4:26 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] xsl to xsl doing it right

At 03:57 PM 4/3/01 -0400, you wrote:
>I'm trying to output an xsl using xsl and am having a hard time
>distinguishing which parts i want the processor to actually process and
>which parts are meant to be straight output.  <xsl:text> doesn't seem to be
>any help and <![CDATA escapes all the brackets making the output useless.
>Any suggestions?


OK, the preferred method is to use namespace-alias:

<xsl:namespace-alias stylesheet-prefix="simon" result-prefix="xsl"/>

and then your xsl looks like this

<xsl:template match="/">
<simon:template match="whatever">....

much cleaner.



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