Subject: [xsl] producing xhtml using xsl From: "Andrew Welch" <andrew@xxxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 20 Apr 2001 16:55:22 +0100 |
Hi, This is probably a stock question, please bear with me... Im trying to produce XHTML output using the following stylesheet: ========= <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes"/> <xsl:template match="/"> <![CDATA[ <?xml version="1.0" encoding="UTF-8" ?> <! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional //EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> ]]> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> .... ========== This fails, as the parser converts < in the cdata section to <. How do I go about outputting the correct xhtml header from a stylesheet?? thanks andrew XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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