Subject: Re: [xsl] xml include From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 11 Apr 2001 12:31:22 +0100 |
Hi, I have two xml files, one of them is included in other: <?xml version="1.0"?> <document xmlns:xinclude="http://www.w3.org/1999/XML/xinclude"> <xinclude:include href="xml.xml"/> </document> And I use this xsl to transform: <?xml version="1.0"?> <xsl:stylesheet version='1.0' xmlns:xsl='http://www.w3.org/1999/XSL/Transform' > <xsl:output method="html" /> <xsl:template match="/"> <H1><xsl:value-of select="//title"/></H1> <H2><xsl:value-of select="//author"/></H2> </xsl:template> </xsl:stylesheet> (xml.xml contains title and author tags) The problem is that xsl cannot read title and author tags ... ? The input to XSL is (logically) a tree. If your XML parser natively supported xml:include (do any?) and "expanded includes" the way that it expands entities, then the tree would have <author> as a descendent of the root node of the input document and your stylesheet would work. As it is, xml:include is probably just seen as a general element by all process concerned so you have to follow the link yourself. <?xml version="1.0"?> <xsl:stylesheet version='1.0' xmlns:xsl='http://www.w3.org/1999/XSL/Transform' xmlns:xinclude="http://www.w3.org/1999/XML/xinclude"> <xsl:output method="html" /> <xsl:template match="/"> <xsl:variable name="x" select="document(document/xinclude:include/@href)"/> <H1><xsl:value-of select="$x//title"/></H1> <H2><xsl:value-of select="$x//author"/></H2> </xsl:template> </xsl:stylesheet> > David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Control Centre. For further information visit http://www.star.net.uk/stats.asp XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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