Subject: Re: [xsl] XSLT FAQ? and really questions From: David Carlisle <davidc@xxxxxxxxx> Date: Sat, 21 Apr 2001 00:48:09 +0100 |
> David, give us a dynamic example. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output encoding="utf-8" indent="yes"/> <xsl:key name="x" match="record/*" use="name()"/> <xsl:template match="/"> <idsets> <xsl:for-each select="/records/record/*[count(.|key('x',name())[1])=1]"> <xsl:element name="{name()}List"> <xsl:copy-of select="/records/record/*[name()=name(current())]"/> </xsl:element> </xsl:for-each> </idsets> </xsl:template> </xsl:stylesheet> _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Control Centre. For further information visit http://www.star.net.uk/stats.asp XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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