Subject: [xsl] how to use an xsd as an xml, or is it an include-problem? From: Rene de Vries <RdVries@xxxxxxxxxxx> Date: Tue, 24 Apr 2001 10:51:01 +0200 |
Hi xsl-ers, I'm new in xml/xsl/xsd/x..-land, and so I hope that my question is an easy-one for you. I'm just in the stadium monkey see, monkey do..... I'm trying to display an xsd in a readable way for end-users. The xml they have to create is database-like, so I want to show a html-table with the database layout: the "fields" for each "datafile". First I want to add a description to the fields, later more compex things like types, required etc. I don't want to change the xsd, so I made a separate description-xml and a main-xml, including the xsd (as an xml) and the description xml: main-xml (including everything I need): <?xml version="1.0" encoding="UTF-8"?> <document xmlns:xinclude="http://www.w3.org/1999/XML/xinclude"> <xinclude:include href="AX_VB.xsd"/> <xinclude:include href="Descriptions_VB.xml"/> </document> a part of my xsd (which I want to display): <?xml version="1.0" encoding="UTF-8"?> <xsd:schema xmlns:xsd="http://www.w3.org/2000/10/XMLSchema"> <xsd:include schemaLocation="Datatypes.xsd"/> <xsd:element name="OfferteAanvraag" type="OfferteAanvraagType"/> <xsd:complexType name="OfferteAanvraagType"> <xsd:sequence> <xsd:element name="Header" type="HeaderType"/> ........ </xsd:sequence> </xsd:complexType> <xsd:complexType name="HeaderType"> <xsd:sequence> <xsd:element name="VerzenderNrHDN" type="HdnNrType"/> <xsd:element name="VerzenderNaam" type="string35Type"/> ........ </xsd:sequence> </xsd:complexType> ...... </xsd:schema> a part of my description-xml: <?xml version="1.0" encoding="ISO-8859-1"?> <Descriptions> <HeaderType> <DescriptionShort>"Standaard header bericht"</DescriptionShort> <DescriptionLong>"Standaard header"</DescriptionLong> <VerzenderNrHDN> <DescriptionShort>"Verzendernummer"</DescriptionShort> <DescriptionLong>"Unieke HDN-nummer verzender"</DescriptionLong> </VerzenderNrHDN> <VerzenderNaam> <DescriptionShort>"Verzendernaam"</DescriptionShort> <DescriptionLong>"Achternaam met voorvoegsel of maatschappijnaam van verzender"</DescriptionLong> </VerzenderNaam> ....... </HeaderType> ....... </Descriptions> my xsl (which doesn't work at all): <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsd="http://www.w3.org/2000/10/XMLSchema" xmlns:xinclude="http://www.w3.org/1999/XML/xinclude"> <xsl:output method="html"/> <xsl:strip-space elements="*"/> <!-- --> <!-- / --> <xsl:template match="/"> <html> <body> <xsl:apply-templates/> </body> </html> </xsl:template> <!-- --> <!-- xsd:element --> <xsl:template match="xsd:element"> <xsl:choose> <xsl:when test="..=/"> <b> Schema: <xsl:value-of select="@name"/> </b> </xsl:when> <xsl:otherwise> <tr> <td width="10%"> <xsl:value-of select="@name"/> </td> <!-- here I want to pull in the Description from the Descriptions.xml --> <xsl:variable name="parent" select="../@name"/> <xsl:variable name="naam" select="@name"/> <xsl:variable name="xxx" select="document(xsd:schema/xinclude:include/@href)"/> <td><xsl:value-of select="$xxx//Descriptions/@parent/@naam/DescriptionShort"/></td> <td width="10%"> <xsl:value-of select="@type"/> </td> </tr> </xsl:otherwise> </xsl:choose> </xsl:template> <!-- --> <!-- xsd:complexType --> <xsl:template match="xsd:complexType"> <xsl:if test="..=/"> <hr/> <b> <xsl:value-of select="@name"/> </b> </xsl:if> <xsl:attribute name="id"><xsl:value-of select="@name"/></xsl:attribute> <xsl:apply-templates select="*"/> </xsl:template> <!-- --> <!-- xsd:sequence --> <xsl:template match="xsd:sequence"> <xsl:if test="..=/"> <hr/> </xsl:if> <table border="1" width="100%"> <tr> <td> <xsl:apply-templates select="*"/> </td> </tr> </table> </xsl:template> <!-- --> </xsl:stylesheet> The only thing I get is a bank page! What do I do wrong???? Greetings Rene { @ @ } ^ \__/ "You don't need eyes to see, you need vision!" XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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