Subject: Re: [xsl] soft returns/wrap not displaying the way I want From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 26 Apr 2001 20:01:28 +0100 |
> 2. display hard returns. You need to define what a hard return is (There is no such concept in HTML). I think you mean a <br/> element. In which case take the replace every newline character by a <br/> element. This is a FAQ and there's code to do this replacement at the faq for this list at http://www.dpawson.co.uk/xsl/break.html > I would somehow nest the xsl select statement in a table in a table if you want or just a div with a specified width. > and have any line break > characters (
) go to <br/> (taking care of the hard > returns/enter yes see the above page so putting it together you just want <xsl:template match="xxxx"> <div width="..."> <xsl:call-template name="substitute"> <xsl:with-param name="string" select="." /> </xsl:call-template> </div> </xsl:template> where the substitute template is defined in the page quoted above. David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Control Centre. For further information visit http://www.star.net.uk/stats.asp XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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