Subject: Re: [xsl] whitespace as a parameter to a template (replace linefe ed with linefeed tab) From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Fri, 1 Jun 2001 08:22:59 +0100 |
Hi James, > I thought about that and so I set my replace string to "foo" and my > by string "bar". Of course the style sheet works just fine with > these non-white-space values. > > I am content with using the other solution you suggested using the > <xsl:text> tags. Sorry to hammer on about it then, but it does sound as if you've missed the quotes around the string value. You need to have two quotes - one set for the select attribute (I use double quotes) and one set around the string that is the value of the expression (I use single quotes): <xsl:with-param name="replace" select="' '" /> If I miss off these single quotes using Saxon then I get the error 'Unexpected token EOF in expression' which is the error that you reported, which backs up my intuition that this is where you're going wrong. The same goes when you're setting other string values, not just whitespace. If you do: <xsl:with-param name="replace" select="foo" /> Then you're setting the $replace parameter to the node set consisting of the foo element children of the current node (which might be an empty node set). The processor won't complain because this is a valid expression. On the other hand, if you do: <xsl:with-param name="replace" select="'foo'" /> Then you're setting it to the string 'foo'. I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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