Subject: [xsl] using a parameter as filterexpression element From: "Mattias Konradsson" <preacher@xxxxxxxxxxx> Date: Fri, 1 Jun 2001 12:47:18 +0200 |
hmm, tricky this, I have an variable like this <xsl:variable name="selection_all" select="//header[Sender = $current_user]"/> and want to make it so that instead of the Sender element in the filter it takes a the element to filter against as an parameter, like <xsl:variable name="selection_all" select="//header[$TheElement = $current_user]"/> doesnt work of course, and I'd guess this doesn't work either: <xsl:variable name="selection_all" select="//header[[local-name() = $TheElement] = $current_user]"/> so, is it possible to pass both the element and the element value in a filter? Best Regards --- Mattias Konradsson XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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